What happens to the weight of an object when it is immersed in a liquid?

According to the Archimedes principle, if an object is immersed in a fluid, it experiences an apparent loss of weight which is equal to the weight of fluid displaced. The buoyant force which acts in the upward direction opposite to the weight of the object causes the apparent loss in weight.

What happens to the weight of a body when immersed in water?

The more a body is immersed in water, the more the weight of the body decreases. … Loss in weight of body = Weight of water (liquid) displaced by the body = Buoyant force or upthrust exerted by water (any liquid) on the body. It was Archimedes who first observed that bodies lose their weight when immersed in water.

How does the buoyant force exerted by the fluid relate to the loss of weight of the metal?

An object will float if the buoyancy force exerted on it by the fluid balances its weight, i.e. if FB=mg F B = mg . But the Archimedes principle states that the buoyant force is the weight of the fluid displaced. So, for a floating object on a liquid, the weight of the displaced liquid is the weight of the object.

What happens to the weight of a stone when it is immersed in water guess and write?

The immersed stone appears to lose weight because the force of buoyancy.

Why does the weight of an object reduce when we immerse it in the water?

Taking up the volume means more water is displaced when the body is submerged so the buoyant force will be larger compared to the weight than it would be for a more dense body. In turn, that means that apparent weight is smaller relative to actual weight for bodies of higher density.

Why does the weight of an object decrease in water?

According to the Archimedes principle, if an object is immersed in a fluid, it experiences an apparent loss of weight which is equal to the weight of fluid displaced. The buoyant force which acts in the upward direction opposite to the weight of the object causes the apparent loss in weight.