What are the critical section problems?

The critical section problem refers to the problem of how to ensure that at most one process is executing its critical section at a given time. Important: Critical sections in different threads are not necessarily the same code segment! sections. sections, then one of these threads will get into the critical section.

What is the critical section problem in OS?

The critical section problem is used to design a protocol followed by a group of processes, so that when one process has entered its critical section, no other process is allowed to execute in its critical section.

Why is solving the critical section problem important?

The critical section problem is used to design a set of protocols which can ensure that the Race condition among the processes will never arise.

What is a critical section problem give the conditions that a solution to the critical section problem must satisfy?

Critical Section Problem

In the entry section, the process requests for entry in the Critical Section. Any solution to the critical section problem must satisfy three requirements: Mutual Exclusion : If a process is executing in its critical section, then no other process is allowed to execute in the critical section.

What are three conditions for solution to critical section problem?

Three must rules which must enforce by critical section are : 1) Mutual Exclusion 2) Process solution 3)Bound waiting. Mutual Exclusion is a special type of binary semaphore which is used for controlling access to the shared resource.

What is Peterson solution OS?

Peterson’s algorithm (or Peterson’s solution) is a concurrent programming algorithm for mutual exclusion that allows two or more processes to share a single-use resource without conflict, using only shared memory for communication.

What are the requirements for the solution to critical section problem Mcq?

Related questions

A minimum of variable(s) is/are required to be shared between processes to solve the critical section problem. Semaphore is a/an to solve the critical section problem. If a process is executing in its critical section, then no other processes can be executing in their critical section.

What is the purpose of critical section and when is a critical section necessary?

A critical section is typically used when a multi-threaded program must update multiple related variables without a separate thread making conflicting changes to that data.

How does Peterson’s solution solve critical section problems?

Peterson’s solution provides a good algorithmic description of solving the critical-section problem and illustrates some of the complexities involved in designing software that addresses the requirements of mutual exclusion, progress, and bounded waiting. Mutual exclusion is preserved.

How does Peterson’s solution provides process synchronization?

Peterson’s Algorithm is used to synchronize two processes. It uses two variables, a bool array flag of size 2 and an int variable turn to accomplish it. In the solution i represents the Consumer and j represents the Producer. … This means that the process wants to execute but it will allow the other process to run first.

Does Peterson’s solution to the mutual exclusion problem?

Peterson’s solution is a classical algorithm for mutual exclusion problem. But rigorous works on analyzing its properties of safety or liveness are rare so far. … The process of proving also produces some good advices on how to programming Peterson’s solution.

What are the challenges with Peterson solution?

(i) This algorithm satisfies the “mutual exclusion”, “progress” and “bounded waiting” condition. ii) This algorithm has a flaw as the variable “turn” can be modified by both processes at the same time. iii) This algorithm may cause “deadlock” if both processes set their flags to True at the same time.

What is hardware solution OS?

The hardware-based solution to critical section problem is based on a simple tool i.e. lock. The solution implies that before entering into the critical section the process must acquire a lock and must release the lock when it exits its critical section. Using of lock also prevent the race condition.

Does Peterson solution satisfy bounded wait?

Here, the Peterson’s solution is considers strict alternation so, alternatively process[0] and process[1] will get access to critical section. Here bounded waiting won’t be satisfied in case e.g. some process gets C.S. repeatedly starving other processes but this situation is not possible because of strict alternation.