What is the energy of a photon that has a frequency of 5.0 10 14hz?

19J
Explanation: h is Planck’s Constant, f is the frequency, c is the speed of light, and λ is the wavelength of the radiation. Calculate the energy of a photon of radiation whose frequency is 5.00×1014Hz . The energy is 3.31×10−19J .

What is the energy of a photon of wavelength 10 10m?

The energy of a photon is10×10-19J.

How do you find the energy of a photon with a frequency?

What is the energy of photon of 10 Mhz frequency?

4. 14×103keV.

What is the energy in J photon of 532 nm light?

Therefore, the green laser with 532 nm of light would an energy of 3.74 x 10–19 J for a single photon, and 225.22 kJ for 1 mole of that photon.

What is the energy in Joules of a photon of 710 nm?

=1.29077⋅10−18 Joules.

What will be the energy of photon having frequency is 10 12 MHz?

Energy of photon whose frequency is 1012 MHz, will beA. 4.14 × 102 eVB.

How do you find the mass of a photon?

Expert Answer:
  1. λ = 589 nm = 5.89 x 10–7 m.
  2. c = 3.0 X 10 8 m/s.
  3. We know , from de Broglie relation ; λ = h/mv(c for photon)
  4. Hence, Mass of photon = h/c λ

How do you find the momentum of a photon?

Photon momentum is given by the equation: p=hλ p = h λ .

When the kinetic energy of an electron is increased?

When the kinetic energy of an electron is increased the wavelength of the associated wave will decrease. This is because wavelength is inversely proportional to the kinetic energy of the electron.

What is the frequency and wavelength of a photon emitted during a transition from n 5 state to?

=4.34×10−7m or 434 nm.

What is the mass of 1 photon?

De-Broglie assumed that the rest mass of photon is about 10 – 54 kg ( 5.610 × 10 – 25 MeV c – 2 ) [1].

What are the frequency and wavelength of a photon?

The amount of energy is directly proportional to the photon’s electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon’s frequency, the higher its energy. Equivalently, the longer the photon’s wavelength, the lower its energy.

What are the frequency and wavelength of a photon emitted during a transition from n 5 state to the n 2 state in the hydrogen spectrum?

What are frequency and wavelength of a photon emitted during a transition from n=5 state to n = 2 state in hydrogen atom? As n1= 2 and n2 = 5, this transition gives rise to a spectral line in the Balmer series. The work function for caesium atom is 1.9 eV.

What are the frequency and wavelength of photon emitted during transition from n 5 to n 2?

What is the wavelength of a photon emitted during a transition from n=5 state to n=2 state in the hydrogen atom? A. 434nm.

What is the wavelength of photon emitted?

= −13.6 × 3 16 eV = 2.55 eV. = 2.55 × 1.6 × 10-19 J 6.63 × 10-34 Js = 6.15 × 1014 Hz. Spring semester 2016 1 Page 2 Modern Physics: Home work 3 Wavelength of the emitted photon can be calculated by using the following equation. = 488 nm.

What is the frequency of a photon emitted from n 6 to n 2?

So, you know that when an electron falls from ni=6 to nf=2 , a photon of wavelength 410 nm is emitted.

What is the frequency of a photon emitted during the electron transition from n 4 to n 2 state in hydrogen atom?

Thus frequency of photon will be f = E/h = 2.55eV/6.63 x 10-34Js= 2.55 x 1.6 x 10-19J/6.63 x 10-34Js= 6.15 x 1014Hz. Wavelength of the emitted photon can be calculated by using the following equation.

What is the wavelength in nm of the photon emitted during the transition from the orbit of n 5 to that of n 2 in hydrogen atom?

450 nm.

What is the wavelength in nm of a photon emitted during a transition from Ni 6 to NF 4?

Calculate the wavelength (in nanometers) emitted by a photon during a transition from n =6 to n = 4 state in the H -atom. or λ=cv=3.0×108ms-11.142×1014=2.63×10-6m.